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NCERT Exemplar · Class 9 Mathematics Quadrilaterals

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EXERCISE 8.2 11–14 (part 4 of 7)

  1. Exercise 11

    Can all the angles of a quadrilateral be acute angles? Give reason for your answer.

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    NCERT’s answer
    No; Angle sum of a quadrilateral is $\displaystyle 360$°.
    \[\angle A + \angle B + \angle C + \angle D = 360^\circ \quad \text{(angle sum of a quadrilateral)} \]If all four angles are acute, each is less than \(\displaystyle 90^\circ\), so:\[\angle A + \angle B + \angle C + \angle D < 360^\circ \]This contradicts the angle sum, so no quadrilateral can have all four angles acute.Answer: No.
  2. Exercise 12

    Can all the angles of a quadrilateral be right angles? Give reason for your answer.

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    NCERT’s answer
    Yes, Angle sum of a quadrilateral is $\displaystyle 360$°.
    \[\angle A + \angle B + \angle C + \angle D = 360^\circ \quad \text{(angle sum of a quadrilateral)} \]If each angle equals \(\displaystyle 90^\circ\):\[4 \times 90^\circ = 360^\circ \]which satisfies the angle sum, so a quadrilateral (e.g. a rectangle) can have all four angles right angles.Answer: Yes.
  3. Exercise 13

    Diagonals of a quadrilateral ABCD bisect each other. If A=35\displaystyle \angle \mathrm{A}=35^{\circ}, determine B\displaystyle \angle \mathrm{B}.

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    NCERT’s answer
    $\displaystyle 145$°
    NCERT_Solution_Class9_Maths_Exemplar_Ch8_Ex8-2_Q13\[OA = OC, \quad OB = OD \quad \text{(diagonals bisect each other)} \]Diagonals bisecting each other make \(\displaystyle ABCD\) a parallelogram.\[\angle A + \angle B = 180^\circ \quad \text{(adjacent angles of a parallelogram)} \] \[35^\circ + \angle B = 180^\circ \] \[\angle B = 145^\circ \]Answer: \(\displaystyle \angle B = 145^\circ\).
  4. Exercise 14

    Opposite angles of a quadrilateral ABCD are equal. If AB=4 cm\displaystyle \mathrm{AB}=4 \mathrm{~cm}, determine CD.

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    NCERT’s answer
    $\displaystyle 4$ cm
    NCERT_Solution_Class9_Maths_Exemplar_Ch8_Ex8-2_Q14\[\angle A = \angle C, \quad \angle B = \angle D \quad \text{(given)} \]Both pairs of opposite angles equal \(\displaystyle \Rightarrow\) \(\displaystyle ABCD\) is a parallelogram.\[CD = AB \quad \text{(opposite sides of a parallelogram)} \] \[CD = 4\ \text{cm} \]Answer: \(\displaystyle CD = 4\) cm.