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NCERT Exemplar · Class 9 Mathematics Polynomials

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EXERCISE 2.1 1–10 (part 1 of 8)

  1. Write the correct answer in each of the following :

    Exercise 1

    Which one of the following is a polynomial? (A) x222x2\displaystyle \frac{x^{2}}{2}-\frac{2}{x^{2}} (B) 2x1\displaystyle \sqrt{2 x}-1 (C) x2+3x32x\displaystyle x^{2}+\frac{3 x^{\frac{3}{2}}}{\sqrt{x}} (D) x1x+1\displaystyle \frac{x-1}{x+1}

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    NCERT’s answer
    (C)
    (C) \(\displaystyle x^{2}+\dfrac{3x^{3/2}}{\sqrt{x}}\) reduces to a polynomial in \(\displaystyle x\).
    \[x^{2}+\frac{3x^{3/2}}{x^{1/2}} = x^{2}+3x^{\frac{3}{2}-\frac{1}{2}} = x^{2}+3x \]
    (A)
    has \(\displaystyle x^{-2}\); (B) has \(\displaystyle x^{1/2}\) -- a negative and a fractional power of \(\displaystyle x\), which a polynomial forbids. (D) is a quotient by the non-constant polynomial \(\displaystyle x+1\).
  2. Exercise 2

    2\displaystyle \sqrt{2} is a polynomial of degree (A) 2\displaystyle 2 (B) 0\displaystyle 0 (C) 1\displaystyle 1 (D) 12\displaystyle \frac{1}{2}

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    NCERT’s answer
    (B)
    (B) \(\displaystyle 0\). \[\sqrt{2} = \sqrt{2}\,x^{0} \] A nonzero constant is a polynomial of degree \(\displaystyle 0\).
  3. Exercise 3

    Degree of the polynomial 4x4+0x3+0x5+5x+7\displaystyle 4 x^{4}+0 x^{3}+0 x^{5}+5 x+7 is (A) 4\displaystyle 4 (B) 5\displaystyle 5 (C) 3\displaystyle 3 (D) 7\displaystyle 7

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    NCERT’s answer
    (A)
    (A) \(\displaystyle 4\). \[4x^{4}+0x^{3}+0x^{5}+5x+7 = 4x^{4}+5x+7 \] Terms with zero coefficient vanish; the highest surviving power of \(\displaystyle x\) is \(\displaystyle 4\).
  4. Exercise 4

    Degree of the zero polynomial is (A) 0\displaystyle 0 (B) 1\displaystyle 1 (C) Any natural number (D) Not defined

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    NCERT’s answer
    (D)
    (D) Not defined. The zero polynomial has no term with a nonzero coefficient, so no highest power of \(\displaystyle x\) exists to call its degree.
  5. Exercise 5

    If p(x)=x222x+1\displaystyle p(x)=x^{2}-2 \sqrt{2} x+1, then p(22)\displaystyle p(2 \sqrt{2}) is equal to (A) 0\displaystyle 0 (B) 1\displaystyle 1 (C) 42\displaystyle 4 \sqrt{2} (D) 82+1\displaystyle 8 \sqrt{2}+1

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    NCERT’s answer
    (B)
    (B) \(\displaystyle 1\). \[p(2\sqrt{2}) = (2\sqrt{2})^{2} - 2\sqrt{2}\cdot(2\sqrt{2}) + 1 \] \[= 8 - 8 + 1 = 1 \]
  6. Exercise 6

    The value of the polynomial 5x4x2+3\displaystyle 5 x-4 x^{2}+3, when x=1\displaystyle x=-1 is (A) - 6\displaystyle 6 (B) 6\displaystyle 6 (C) 2\displaystyle 2 (D) -2\displaystyle 2

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    NCERT’s answer
    (A)
    (A) \(\displaystyle -6\). \[5(-1) - 4(-1)^{2} + 3 = -5 - 4 + 3 = -6 \]
  7. Exercise 7

    If p(x)=x+3\displaystyle p(x)=x+3, then p(x)+p(x)\displaystyle p(x)+p(-x) is equal to (A) 3\displaystyle 3 (B) 2x\displaystyle 2 x (C) 0\displaystyle 0 (D) 6\displaystyle 6

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    NCERT’s answer
    (D)
    (D) \(\displaystyle 6\). \[p(x)+p(-x) = (x+3)+(-x+3) = 6 \]
  8. Exercise 8

    Zero of the zero polynomial is (A) 0\displaystyle 0 (B) 1\displaystyle 1 (C) Any real number (D) Not defined

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    NCERT’s answer
    (C)
    (C) Any real number. \[p(x) = 0 \quad \text{for every } x \] The zero polynomial vanishes at every value of \(\displaystyle x\), so each real number is a zero of it.
  9. Exercise 9

    Zero of the polynomial p(x)=2x+5\displaystyle p(x)=2 x+5 is (A) 25\displaystyle -\frac{2}{5} (B) 52\displaystyle -\frac{5}{2} (C) 25\displaystyle \frac{2}{5} (D) 52\displaystyle \frac{5}{2}

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    NCERT’s answer
    (B)
    (B) \(\displaystyle -\dfrac{5}{2}\). \[2x+5 = 0 \implies x = -\frac{5}{2} \]
  10. Exercise 10

    One of the zeroes of the polynomial 2x2+7x4\displaystyle 2 x^{2}+7 x-4 is (A) 2\displaystyle 2 (B) 12\displaystyle \frac{1}{2} (C) 12\displaystyle -\frac{1}{2} (D) -2\displaystyle 2

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    NCERT’s answer
    (B)
    (B) \(\displaystyle \dfrac{1}{2}\). \[2x^{2}+7x-4 = (2x-1)(x+4) \] \[2x-1=0 \implies x=\frac{1}{2} \]