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NCERT Exemplar · Class 12 Mathematics Matrices

101 questions · 101 still being checked

EXERCISE 3.3 81–90 (part 9 of 10)

  1. Fill in the blanks in each of the Exercises $\displaystyle 68$–81.

    Exercise 81

    In applying one or more row operations while finding A−1\displaystyle \mathrm{A}^{-1} by elementary row operations, we obtain all zeros in one or more, then A−1\displaystyle \mathrm{A}^{-1} ____.

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    NCERT’s answer
    does not exist
    does not exist. A zero row in the reduced left-hand matrix forces \(\displaystyle |A| = 0\).\[E_k \cdots E_2 E_1 A = B \quad \text{(} B \text{ has a zero row)} \]\[|B| = 0 \]\[|E_k| \cdots |E_1|\,|A| = |B| = 0, \quad |E_i| \neq 0 \]\[|A| = 0 \;\Rightarrow\; A \text{ is singular} \]
  2. State Exercises $\displaystyle 82$ to $\displaystyle 101$ which of the following statements are True or False

    Exercise 82

    A matrix denotes a number.

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    NCERT’s answer
    False
    False. A matrix is a rectangular array of numbers; only its determinant is a single number.\[A = \begin{bmatrix} 1 & 2 \\ 3 & 4 \end{bmatrix} \quad \text{(4 entries, order } 2 \times 2 \text{)} \]\[|A| = 1 \cdot 4 - 2 \cdot 3 = -2 \quad \text{(a number)} \]
  3. Exercise 83

    Matrices of any order can be added.

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    NCERT’s answer
    False
    False. Addition is entrywise, so both matrices must have the same order.\[A = \begin{bmatrix} 1 & 2 \\ 3 & 4 \end{bmatrix}_{2 \times 2}, \quad B = \begin{bmatrix} 1 & 2 & 3 \\ 4 & 5 & 6 \end{bmatrix}_{2 \times 3} \]\[A + B \quad \text{is not defined (3 and 6 have no partner in } A \text{)} \]
  4. Exercise 84

    Two matrices are equal if they have same number of rows and same number of columns.

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    NCERT’s answer
    False
    False. Equal matrices need the same order and equal corresponding entries.\[\begin{bmatrix} 1 & 2 \\ 3 & 4 \end{bmatrix} \neq \begin{bmatrix} 1 & 2 \\ 3 & 5 \end{bmatrix} \quad \text{(both } 2 \times 2 \text{)} \]
  5. Exercise 85

    Matrices of different order can not be subtracted.

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    NCERT’s answer
    True
    True. Subtraction is entrywise, so it needs the same order, as addition does.\[A - B = A + (-B) \]\[(A - B)_{ij} = a_{ij} - b_{ij} \quad \text{(needs } b_{ij} \text{ for every } a_{ij} \text{)} \]
  6. Exercise 86

    Matrix addition is associative as well as commutative.

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    NCERT’s answer
    True
    True. Both laws follow entrywise from the same laws for real numbers.\[(A+B)_{ij} = a_{ij} + b_{ij} = b_{ij} + a_{ij} = (B+A)_{ij} \]\[\big((A+B)+C\big)_{ij} = (a_{ij} + b_{ij}) + c_{ij} = a_{ij} + (b_{ij} + c_{ij}) = \big(A+(B+C)\big)_{ij} \]
  7. Exercise 87

    Matrix multiplication is commutative.

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    NCERT’s answer
    False
    False. Counterexample:\[A = \begin{bmatrix} 1 & 2 \\ 3 & 4 \end{bmatrix}, \quad B = \begin{bmatrix} 0 & 1 \\ 1 & 0 \end{bmatrix} \]\[AB = \begin{bmatrix} 2 & 1 \\ 4 & 3 \end{bmatrix} \]\[BA = \begin{bmatrix} 3 & 4 \\ 1 & 2 \end{bmatrix} \neq AB \]
  8. Exercise 88

    A square matrix where every element is unity is called an identity matrix.

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    NCERT’s answer
    False
    False. An identity matrix has $\displaystyle 1$ on the diagonal and $\displaystyle 0$ elsewhere, and satisfies \(\displaystyle I^2 = I\). The all-ones matrix does not:\[J = \begin{bmatrix} 1 & 1 \\ 1 & 1 \end{bmatrix} \]\[J^2 = \begin{bmatrix} 2 & 2 \\ 2 & 2 \end{bmatrix} \neq J \]
  9. Exercise 89

    If A and B are two square matrices of the same order, then A+B=B+A\displaystyle \mathrm{A}+\mathrm{B}=\mathrm{B}+\mathrm{A}.

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    NCERT’s answer
    True
    True. Matrices add entry by entry, and addition of numbers is commutative. \[(A+B)_{ij} = a_{ij} + b_{ij} \] \[a_{ij} + b_{ij} = b_{ij} + a_{ij} = (B+A)_{ij} \] \[\therefore\; A + B = B + A \]
  10. Exercise 90

    If A and B are two matrices of the same order, then A−B=B−A\displaystyle \mathrm{A}-\mathrm{B}=\mathrm{B}-\mathrm{A}.

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    NCERT’s answer
    False
    False. The equality forces \(\displaystyle A = B\), which is not true in general. \[A - B = B - A \;\Rightarrow\; 2A = 2B \;\Rightarrow\; A = B \] Counter-example: \[A=\begin{bmatrix}1&0\\0&1\end{bmatrix},\quad B=\begin{bmatrix}0&0\\0&0\end{bmatrix} \] \[A-B=\begin{bmatrix}1&0\\0&1\end{bmatrix} \neq \begin{bmatrix}-1&0\\0&-1\end{bmatrix}=B-A \]