Physics · 2024
JEE Main · 8 April 2024, Shift 1 · Q48
Young's modulus is determined by the equation given by Y =49000 m/l dyne/(cm^2) where M is the mass and l is the extension of wire used in the…
Young's modulus is determined by the equation given by $\displaystyle \mathrm{Y}=49000 \frac{m}{l} \frac{\mathrm{dyne}}{\mathrm{cm}^2}$ where $\displaystyle M$ is the mass and $\displaystyle l$ is the extension of wire used in the experiment. Now error in Young modules $\displaystyle (Y)$ is estimated by taking data from $\displaystyle M-l$ plot in graph paper. The smallest scale divisions are $\displaystyle 5$ g and $\displaystyle 0.02$ cm along load axis and extension axis respectively. If the value of $\displaystyle M$ and $\displaystyle l$ are $\displaystyle 500$ g and $\displaystyle 2$ cm respectively then percentage error of $\displaystyle Y$ is :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 2$ %
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.