Physics · 2024
JEE Main · 29 January 2024, Shift 2 · Q31
A physical quantity Q is found to depend on quantities a, b, c by the relation Q=(a^4 b^3)/c^2. The percentage error in a, b and c are 3 %, 4 % and 5…
A physical quantity $\displaystyle Q$ is found to depend on quantities $\displaystyle a, b, c$ by the relation $\displaystyle Q=\frac{a^4 b^3}{c^2}$. The percentage error in $\displaystyle a, b$ and $\displaystyle c$ are $\displaystyle 3 \%, 4 \%$ and $\displaystyle 5 \%$ respectively. Then, the percentage error in $\displaystyle Q$ is :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 34$%
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.