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Physics · 2024

JEE Main · 29 January 2024, Shift 1 · Q31

The resistance R=V/I where V =(200 ± 5) V and I=(20 ± 0.2) A, the percentage error in the measurement of R is:

The resistance $\displaystyle R=\frac{V}{I}$ where $\displaystyle \mathrm{V}=(200 \pm 5) \mathrm{V}$ and $\displaystyle I=(20 \pm 0.2) \mathrm{A}$, the percentage error in the measurement of R is :
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.