SolveIt is under development
SolveItJEE Main
Physics · 2019

JEE Main · 11 January 2019, Shift 2 · Q9

When 100 g of a liquid A at 100^° C is added to 50 g of a liquid B at temperature 75^° C, the temperature of the mixture becomes 90°C. The…

When $\displaystyle 100$ g of a liquid A at $\displaystyle 100^{\circ} \mathrm{C}$ is added to $\displaystyle 50$ g of a liquid B at temperature $\displaystyle 75^{\circ} \mathrm{C}$, the temperature of the mixture becomes $\displaystyle 90$°C. The temperature of the mixture, if $\displaystyle 100$ g of liquid A at $\displaystyle 100$°C is added to $\displaystyle 50$ g of liquid B at $\displaystyle 50$°C, will be :
ShareWhatsAppTelegram

More from Thermal Expansion and Calorimetry

JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.