Physics · 2020
JEE Main · 7 January 2020, Shift 2 · Q22
M grams of steam at 100^° C is mixed with 200 g of ice at its melting point in a thermally insulated container. If it produces liquid water at 40°C…
M grams of steam at $\displaystyle 100^{\circ} \mathrm{C}$ is mixed with $\displaystyle 200$ g of ice at its melting point in a thermally insulated container. If it produces liquid water at $\displaystyle 40$°C [heat of vaporization of water is $\displaystyle 540 \mathrm{cal} / \mathrm{g}$ and heat of fusion of ice is $\displaystyle 80$ cal/g], the value of M is \_\_\_\_.
Official answer
40
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