Physics · 2016
JEE Main · 9 April 2016, Shift 1 · Q10
Two particles are performing simple harmonic motion in a straight line about the same equilibrium point. The amplitude and time period for both…
Two particles are performing simple harmonic motion in a straight line about the same equilibrium point. The amplitude and time period for both particles are same and equal to $\displaystyle A$ and $\displaystyle T$, respectively. At time $\displaystyle t=0$ one particle has displacement $\displaystyle A$ while the other one has displacement $\displaystyle \frac{-A}{2}$ and they are moving towards each other. If they cross each other at time $\displaystyle t$, then $\displaystyle t$ is :
Official answer
(1)
$\displaystyle \frac{T}{6}$
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JEE Main 2016 Physics question, with the answer from NTA’s final answer key. Where our answers come from.