Physics · 2018
JEE Main · 16 April 2018, Shift 1 · Q12
A particle executes simple harmonic motion and is located at x= a, b and c at times t_o, 2 t_o and 3 t_o respectively. The frequency of the…
A particle executes simple harmonic motion and is located at $\displaystyle x=\mathrm{a}, \mathrm{b}$ and c at times $\displaystyle \mathrm{t}_{\mathrm{o}}, 2 \mathrm{t}_{\mathrm{o}}$ and $\displaystyle 3 \mathrm{t}_{\mathrm{o}}$ respectively. The frequency of the oscillation is :
Official answer
(1)
$\displaystyle \frac{1}{2 \pi t_o} \cos ^{-1}\left(\frac{a+c}{2 b}\right)$
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JEE Main 2018 Physics question, with the answer from NTA’s final answer key. Where our answers come from.