Physics · 2021
JEE Main · 24 February 2021, Shift 2 · Q10
Two electrons each are fixed at a distance ' 2 d '. A third charge proton placed at the midpoint is displaced slightly by a distance x(x ≪ d)…
Two electrons each are fixed at a distance ' $\displaystyle 2 d$ '. A third charge proton placed at the midpoint is displaced slightly by a distance $\displaystyle x(x \ll d)$ perpendicular to the line joining the two fixed charges. Proton will execute simple harmonic motion having angular frequency : ( $\displaystyle m=$ mass of charged particle)
Official answer
(1)
$\displaystyle \left(\frac{q^2}{2 \pi \varepsilon_0 m d^3}\right)^{\frac{1}{2}}$
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.