The electric field in a region is given by E =(3/5 E_0 i +4/5 E_0 j ) N/C. The ratio of flux of reported field through the rectangular surface of…

The electric field in a region is given by $\displaystyle \overrightarrow{\mathrm{E}}=\left(\frac{3}{5} \mathrm{E}_0 \hat{i}+\frac{4}{5} \mathrm{E}_0 \hat{j}\right) \frac{\mathrm{N}}{\mathrm{C}}$. The ratio of flux of reported field through the rectangular surface of area $\displaystyle 0.2 \mathrm{~m}^2$ (parallel to $\displaystyle y-z$ plane) to that of the surface of area $\displaystyle 0.3 \mathrm{~m}^2$ (parallel to $\displaystyle x-z$ plane) is a: b , where $\displaystyle \mathrm{a}=$ \_\_\_\_. [Here $\displaystyle \hat{i}, \hat{j}$ and $\displaystyle \hat{k}$ are unit vectors along $\displaystyle x, y$ and $\displaystyle z$-axes respectively]