Physics · 2025
JEE Main · 23 January 2025, Shift 2 · Q38
Two charges 7 μ c and -4 μ c are placed at ( -7 cm, 0,0 ) and ( 7 cm, 0,0 ) respectively. Given, ε_0=8.85 × 10^-12 C^2 N^-1 m^-2, the electrostatic…
Two charges $\displaystyle 7 \mu \mathrm{c}$ and $\displaystyle -4 \mu \mathrm{c}$ are placed at ( $\displaystyle -7 \mathrm{~cm}, 0,0$ ) and ( $\displaystyle 7 \mathrm{~cm}, 0,0$ ) respectively. Given, $\displaystyle \epsilon_0=8.85 \times 10^{-12} \mathrm{C}^2 \mathrm{~N}^{-1} \mathrm{~m}^{-2}$, the electrostatic potential energy of the charge configuration is :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 1.8$ J
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JEE Main 2025 Physics question, with the answer from NTA’s final answer key. Where our answers come from.