The K_α X-ray of molybdenum has wavelength 0.071 nm. If the energy of a molybdenum atom with a K electron knocked out is 27.5 keV, the energy of this…

The $\displaystyle \mathrm{K}_\alpha$ X-ray of molybdenum has wavelength $\displaystyle 0.071$ nm . If the energy of a molybdenum atom with a K electron knocked out is $\displaystyle 27.5$ keV , the energy of this atom when an L electron is knocked out will be \_\_\_\_ keV. (Round off to the nearest integer) $\displaystyle \left[\mathrm{h}=4.14 \times 10^{-15} \mathrm{eVs}, \mathrm{c}=3 \times 10^8 \mathrm{~ms}^{-1}\right]$