Physics · 2014
JEE Main · 19 April 2014, Shift 1 · Q15
The total length of a sonometer wire between fixed ends is 110 cm. Two bridges are placed to divide the length of wire in ratio 6: 3: 2. The tension…
The total length of a sonometer wire between fixed ends is $\displaystyle 110$ cm. Two bridges are placed to divide the length of wire in ratio $\displaystyle 6$ : $\displaystyle 3$ : 2. The tension in the wire is $\displaystyle 400$ N and the mass per unit length is $\displaystyle 0.01$ kg/m. What is the minimum common frequency with which three parts can vibrate ?
Official answer
(2)
$\displaystyle 1000$ Hz
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JEE Main 2014 Physics question, with the answer from NTA’s final answer key. Where our answers come from.