Physics · 2019
JEE Main · 9 April 2019, Shift 1 · Q13
A string is clamped at both the ends and it is vibrating in its 4^th harmonic. The equation of the stationary wave is Y =0.3 sin (0.157 x) cos (200 π…
A string is clamped at both the ends and it is vibrating in its $\displaystyle 4^{\text {th }}$ harmonic. The equation of the stationary wave is $\displaystyle \mathrm{Y}=0.3 \sin (0.157 x) \cos (200 \pi \mathrm{t})$. The length of the string is : (All quantities are in SI units.)
Official answer
(1)
$\displaystyle 80$ m
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.