Physics · 2025
JEE Main · 22 January 2025, Shift 2 · Q28
The torque due to the force (2 i + j +2 k ) about the origin, acting on a particle whose position vector is ( i + j + k ), would be
The torque due to the force $\displaystyle (2 \hat{i}+\hat{j}+2 \hat{k})$ about the origin, acting on a particle whose position vector is $\displaystyle (\hat{i}+\hat{j}+\hat{k})$, would be
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle \hat{i}-\hat{k}$
More from Rotational Motion
- The moment of inertia of a circular ring of mass M and diameter r about a tangential axis lying in the plane of the ring is:2025
- A solid sphere (A) of mass 5 m and a spherical shell (B) of mass m, both having same radius, are placed on a rough surface. When a force of same…2026
- Moment of inertia about an axis A B for a rod of mass 40 kg and length 3 m is same as that of a solid sphere of mass of 10 kg and radius R about an…2026
- A solid sphere of mass 5 kg and radius 10 cm is kept in contact with another solid sphere of mass 10 kg and radius 20 cm. The moment of inertia of…2026
- A wheel is rolling on a plane surface. The speed of a particle on the highest point of the rim is 8 m / s. The speed of the particle on the rim of…2025
- A solid sphere of radius 4 cm and mass 5 kg is rotating (rotation axis is passing through the centre of the sphere) with an angular velocity of 1200…2026
- Three equal masses m are kept at vertices (A, B, C) of an equilateral triangle of side a in free space. At t=0, they are given an initial velocity…2025
- A cord of negligible mass is wound around the rim of a wheel supported by spokes with negligible mass. The mass of wheel is 10 kg and radius is 10 cm…2025
JEE Main 2025 Physics question, with the answer from NTA’s final answer key. Where our answers come from.