Physics · 2024
JEE Main · 9 April 2024, Shift 2 · Q41
The temperature of a gas is -78^° C and the average translational kinetic energy of its molecules is K. The temperature at which the average…
The temperature of a gas is $\displaystyle -78^{\circ} \mathrm{C}$ and the average translational kinetic energy of its molecules is K . The temperature at which the average translational kinetic energy of the molecules of the same gas becomes $\displaystyle 2$ K is :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 117^{\circ} \mathrm{C}$
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.