Physics · 2024
JEE Main · 29 January 2024, Shift 2 · Q39
The temperature of a gas having 2.0 × 10^25 molecules per cubic meter at 1.38 atm (Given, k =1.38 × 10^-23 JK^-1 ) is:
The temperature of a gas having $\displaystyle 2.0 \times 10^{25}$ molecules per cubic meter at $\displaystyle 1.38$ atm (Given, $\displaystyle \mathrm{k}=1.38 \times 10^{-23} \mathrm{JK}^{-1}$ ) is :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 500$ K
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.