Physics · 2021
JEE Main · 24 February 2021, Shift 2 · Q24
The root mean square speed of molecules of a given mass of a gas at 27°C and 1 atmosphere pressure is 200 ms^-1. The root mean square speed of…
The root mean square speed of molecules of a given mass of a gas at $\displaystyle 27$°C and $\displaystyle 1$ atmosphere pressure is $\displaystyle 200 \mathrm{~ms}^{-1}$. The root mean square speed of molecules of the gas at $\displaystyle 127^{\circ} \mathrm{C}$ and $\displaystyle 2$ atmosphere pressure is $\displaystyle \frac{x}{\sqrt{3}} \mathrm{~ms}^{-1}$. The value of $\displaystyle x$ will be \_\_\_\_.
Official answer
400
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.