The position vector of 1 kg object is r =(3 i - j ) m and its velocity v =(3 j + k ) ms^-1. The magnitude of its angular momentum is √ x Nm where x…

The position vector of $\displaystyle 1$ kg object is $\displaystyle \overrightarrow{\mathrm{r}}=(3 \hat{\mathrm{i}}-\hat{\mathrm{j}}) \mathrm{m}$ and its velocity $\displaystyle \overrightarrow{\mathrm{v}}=(3 \hat{\mathrm{j}}+\hat{\mathrm{k}}) \mathrm{ms}^{-1}$. The magnitude of its angular momentum is $\displaystyle \sqrt{\mathrm{x}} \mathrm{Nm}$ where $\displaystyle x$ is \_\_\_\_.