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Physics · 2021

JEE Main · 4 August 2021, Shift 2 · Q18

The position time relation of a body of mass 0.02 kg is given by (one-dimensional motion) x =9 cm ( for t =3,9,15,21 s … … …..); x =0 cm ( for t…

The position time relation of a body of mass $\displaystyle 0.02$ kg is given by (one-dimensional motion) $$\begin{aligned} & \mathrm{x}=9 \mathrm{~cm}(\text { for } \mathrm{t}=3,9,15,21 \mathrm{~s} \ldots \ldots \ldots . .) \\ & \mathrm{x}=0 \mathrm{~cm}(\text { for } \mathrm{t}=0,6,12,18,24 \mathrm{~s} \ldots \ldots \ldots . .) \end{aligned} $$ If the time between two consecutive impulse is ' $\displaystyle 3$ s ', find the magnitude of each impulse.
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.