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Physics · 2023

JEE Main · 8 April 2023, Shift 1 · Q53

The moment of inertia of a semicircular ring about an axis, passing through the center and perpendicular to the plane of ring, is 1/x MR^2, where R…

The moment of inertia of a semicircular ring about an axis, passing through the center and perpendicular to the plane of ring, is $\displaystyle \frac{1}{x} \mathrm{MR}^2$, where R is the radius and $\displaystyle M$ is the mass of the semicircular ring. The value of $\displaystyle x$ will be $\displaystyle \_\_\_\_$.
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.