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Physics · 2024

JEE Main · 29 January 2024, Shift 1 · Q57

The magnetic potential due to a magnetic dipole at a point on its axis situated at a distance of 20 cm from its center is 1.5 × 10^-5 Tm. The…

The magnetic potential due to a magnetic dipole at a point on its axis situated at a distance of $\displaystyle 20$ cm from its center is $\displaystyle 1.5 \times 10^{-5} \mathrm{Tm}$. The magnetic moment of the dipole is $\displaystyle \_\_\_\_$ $\displaystyle A m^2$. (Given : $\displaystyle \frac{\mu_o}{4 \pi}=10^{-7} T m A^{-1}$ )
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.