Physics · 2024
JEE Main · 4 April 2024, Shift 2 · Q43
The magnetic moment of a bar magnet is 0.5 Am^2. It is suspended in a uniform magnetic field of 8 × 10^-2 T. The work done in rotating it from its…
The magnetic moment of a bar magnet is $\displaystyle 0.5 \mathrm{Am}^2$. It is suspended in a uniform magnetic field of $\displaystyle 8 \times 10^{-2} \mathrm{~T}$. The work done in rotating it from its most stable to most unstable position is:
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 8 \times 10^{-2} \mathrm{~J}$
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.