Physics · 2024
JEE Main · 9 April 2024, Shift 2 · Q50
The magnetic field in a plane electromagnetic wave is B_y =(3.5 × 10^-7) sin (1.5 × 10^3 x+0.5 × 10^11 t) T. The corresponding electric field will be:
The magnetic field in a plane electromagnetic wave is $\displaystyle \mathrm{B}_{\mathrm{y}}=\left(3.5 \times 10^{-7}\right) \sin \left(1.5 \times 10^3 x+0.5 \times 10^{11} t\right) \mathrm{T}$. The corresponding electric field will be :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle E_z=105 \sin \left(1.5 \times 10^3 x+0.5 \times 10^{11} t\right) \mathrm{Vm}^{-1}$
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.