Physics · 2024
JEE Main · 6 April 2024, Shift 2 · Q45
In the given electromagnetic wave E_y =600 sin (ω t - kx ) Vm^-1, intensity of the associated light beam is (in W / m^2: (Given ε_0=9 × 10^-12 C^2…
In the given electromagnetic wave $\displaystyle \mathrm{E}_{\mathrm{y}}=600 \sin (\omega \mathrm{t}-\mathrm{kx}) \mathrm{Vm}^{-1}$, intensity of the associated light beam is (in $\displaystyle \mathrm{W} / \mathrm{m}^2$ : (Given $\displaystyle \epsilon_0=9 \times 10^{-12} \mathrm{C}^2 \mathrm{~N}^{-1} \mathrm{~m}^{-2}$ )
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 486$
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.