Physics · 2023
JEE Main · 30 January 2023, Shift 1 · Q24
The general displacement of a simple harmonic oscillator is x= A sin ω t. Let T be its time period. The slope of its potential energy ( U ) - time (…
The general displacement of a simple harmonic oscillator is $\displaystyle x=\mathrm{A} \sin \omega \mathrm{t}$. Let T be its time period. The slope of its potential energy $\displaystyle (\mathrm{U})$ - time ( t ) curve will be maximum when $\displaystyle \mathrm{t}=\frac{\mathrm{T}}{\beta}$. The value of $\displaystyle \beta$ is $\displaystyle \_\_\_\_$.
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From NTA’s final answer key for this paper.
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.