Physics · 2023
JEE Main · 29 January 2023, Shift 2 · Q27
A particle of mass 250 g executes a simple harmonic motion under a periodic force F =(-25 x) N. The particle attains a maximum speed of 4 m / s…
A particle of mass $\displaystyle 250$ g executes a simple harmonic motion under a periodic force $\displaystyle \mathrm{F}=(-25 x) \mathrm{N}$. The particle attains a maximum speed of $\displaystyle 4 \mathrm{~m} / \mathrm{s}$ during its oscillation. The amplitude of the motion is $\displaystyle \_\_\_\_$ cm.
Official answer
From NTA’s final answer key for this paper.
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.