Physics · 2026
JEE Main · 2 April 2026, Shift 2 · Q45
The equation of motion of a particle is given by x=a sin (50 t+π / 3) cm. The particle will come to rest at time t_1 and it will have zero…
The equation of motion of a particle is given by $\displaystyle x=a \sin (50 t+\pi / 3) \mathrm{cm}$. The particle will come to rest at time $\displaystyle t_1$ and it will have zero acceleration at time $\displaystyle t_2$. The $\displaystyle t_1$ and $\displaystyle t_2$ respectively are $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle \frac{\pi}{300} s, \frac{\pi}{75} s$
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.