Physics · 2026
JEE Main · 6 April 2026, Shift 1 · Q37
A particle is executing simple harmonic motion. Its amplitude is A and time period is 5 sec. The time required by it to move from x=A to x=A/(√ 2) is…
A particle is executing simple harmonic motion. Its amplitude is $\displaystyle A$ and time period is $\displaystyle 5$ sec. The time required by it to move from $\displaystyle x=A$ to $\displaystyle x=\frac{A}{\sqrt{2}}$ is
$\displaystyle \_\_\_\_$ sec.
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 5$/$\displaystyle 8$
More from Simple Harmonic Motion
- The velocity of a particle executing simple harmonic motion along x -axis is described as v^2=50-x^2, where x…2026
- Match List - I with List - II. List - I List - II A. sin^2 ω t I. Periodic with time period T=(π)/(ω) but not…2026
- A uniform disc of radius R and mass M is free to oscillate about the axis A as shown in the figure. For small…2026
- The equation of motion of a particle is given by x=a sin (50 t+π / 3) cm. The particle will come to rest at…2026
- A spring stretches by 2 mm when it is loaded with a mass of 200 g. From equilibrium position the mass is…2026
- The frequency of oscillation of a mass m suspended by a spring is v_1. If the length of the spring is cut to…2026
JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.