Physics · 2025
JEE Main · 23 January 2025, Shift 2 · Q35
The equation of a transverse wave travelling along a string is y(x, t)=4.0 sin [20 × 10^-3 x+600 t] mm, where x is in mm and t is in second. The…
The equation of a transverse wave travelling along a string is $\displaystyle y(x, t)=4.0 \sin \left[20 \times 10^{-3} x+600 t\right] \mathrm{mm}$, where $\displaystyle x$ is in mm and $\displaystyle t$ is in second. The velocity of the wave is :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle -30 \mathrm{~m} / \mathrm{s}$
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JEE Main 2025 Physics question, with the answer from NTA’s final answer key. Where our answers come from.