Physics · 2025
JEE Main · 4 April 2025, Shift 2 · Q34
Displacement of a wave is expressed as x( t )=5 cos (628 t +(π)/2) m. The wavelength of the wave when its velocity is 300 m/s is: (π=3.14)
Displacement of a wave is expressed as $\displaystyle x(\mathrm{t})=5 \cos \left(628 \mathrm{t}+\frac{\pi}{2}\right) \mathrm{m}$. The wavelength of the wave when its velocity is $\displaystyle 300$ m/s is :
$$(\pi=3.14)
$$
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 3 \mathrm{~m}$
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JEE Main 2025 Physics question, with the answer from NTA’s final answer key. Where our answers come from.