Physics · 2022
JEE Main · 28 July 2022, Shift 1 · Q47
The equation λ=1.227/x nm can be used to find the de-Brogli wavelength of an electron. In this equation x stands for: Where m= mass of electron; P=…
The equation $\displaystyle \lambda=\frac{1.227}{x} \mathrm{~nm}$ can be used to find the de-Brogli wavelength of an electron.
In this equation $\displaystyle x$ stands for :
Where
$$\begin{aligned}
& m=\text { mass of electron } \\
& P=\text { momentum of electron } \\
& K=\text { Kinetic energy of electron } \\
& V=\text { Accelerating potential in volts for electron }
\end{aligned}
$$
Official answer
(4)
$\displaystyle \sqrt{V}$
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.