The electric field of light wave is given as E =10^-3 cos ((2 π x)/(5 × 10^-7)-2 π × 6 × 10^14 t ) x N/C This light falls on a metal plate of work…

The electric field of light wave is given as $$\overrightarrow{\mathrm{E}}=10^{-3} \cos \left(\frac{2 \pi x}{5 \times 10^{-7}}-2 \pi \times 6 \times 10^{14} \mathrm{t}\right) \hat{x} \frac{\mathrm{~N}}{\mathrm{C}} $$ This light falls on a metal plate of work function $\displaystyle 2$ eV . The stopping potential of the photo-electrons is : Given, $\displaystyle \mathrm{E}($ in eV$\displaystyle )=\frac{12375}{\lambda(\text { in } \AA)}$