Physics · 2021
JEE Main · 31 August 2021, Shift 1 · Q29
The electric field in an electromagnetic wave is given by E =(50 NC^-1) sin ω( t -x / c ) The energy contained in a cylinder of volume V is 5.5 ×…
The electric field in an electromagnetic wave is given by
$$\mathrm{E}=\left(50 \mathrm{NC}^{-1}\right) \sin \omega(\mathrm{t}-x / \mathrm{c})
$$
The energy contained in a cylinder of volume V is $\displaystyle 5.5 \times 10^{-12} \mathrm{~J}$. The value of V is
\_\_\_\_ $\displaystyle \mathrm{cm}^3$.
$$\text { (given } \epsilon_0=8.8 \times 10^{-12} \mathrm{C}^2 \mathrm{~N}^{-1} \mathrm{~m}^{-2} \text { ) }
$$
Official answer
500
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.