Physics · 2026
JEE Main · 21 January 2026, Shift 1 · Q31
The electric field in a plane electromagnetic wave is given by: E_y=69 sin [0.6 × 10^3 x-1.8 × 10^11 t] V / m. The expression for magnetic field…
The electric field in a plane electromagnetic wave is given by :
$$E_y=69 \sin \left[0.6 \times 10^3 x-1.8 \times 10^{11} t\right] \mathrm{V} / \mathrm{m} .
$$
The expression for magnetic field associated with this electromagnetic wave is $\displaystyle \_\_\_\_$ T.
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle B_z=2.3 \times 10^{-7} \sin \left[0.6 \times 10^3 x-1.8 \times 10^{11} t\right]$
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.