Physics · 2026
JEE Main · 5 April 2026, Shift 1 · Q37
A displacement current of 4.0 A can be set up in the space between two parallel plates of 6 μ F capacitor. The rate of change of potential difference…
A displacement current of $\displaystyle 4.0$ A can be set up in the space between two parallel plates of $\displaystyle 6 \mu \mathrm{~F}$ capacitor. The rate of change of potential difference across the plates of the capacitor is nearly $\displaystyle \alpha \times 10^6 \mathrm{~V} / \mathrm{s}$. The value of $\displaystyle \alpha$ is $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 0.67$
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.