Physics · 2017
JEE Main · 9 April 2017, Shift 1 · Q21
The electric field component of a monochromatic radiation is given by E =2 E_0 i cos k z cos ω t Its magnetic field B is then given by:
The electric field component of a monochromatic radiation is given by
$$\overrightarrow{\mathrm{E}}=2 \mathrm{E}_0 \hat{i} \cos \mathrm{k} z \cos \omega \mathrm{t}
$$
Its magnetic field $\displaystyle \overrightarrow{\mathrm{B}}$ is then given by :
Official answer
(3)
$\displaystyle \frac{2 \mathrm{E}_0}{\mathrm{c}} \hat{j} \sin \mathrm{k} z \sin \omega \mathrm{t}$
More from Electromagnetic Waves
- An electromagnetic wave of frequency 3 GHz enters a dielectric medium of relative electric permittivity 2.25 from vacuum. The wavelength of this wave…2021
- The electric field in an electromagnetic wave is given by E=56.5 sin ω(t-x / c) NC^-1. Find the intensity of the wave if it is propagating along x…2022
- The equation of the electric field of an electromagnetic wave propagating through free space is given by: E=√377 sin (6.27 × 10^3 t-2.09 × 10^-5 x) N…2026
- Given below are two statements: Statement I: A time varying electric field is a source of changing magnetic field and vice-versa. Thus a disturbance…2022
- Choose the correct answer from the options given below:2026
- The electric field of a plane electromagnetic wave is given by E=E_0 i cos (k z) cos (ω t) The corresponding magnetic field B is then given by:2019
- A point source of light is placed at the centre of curvature of a hemispherical surface. The source emits a power of 24 W. The radius of curvature of…2023
- Light is incident normally on a completely absorbing surface with an energy flux of 25 Wcm^-2. If the surface has an area of 25 cm^2, the momentum…2019
JEE Main 2017 Physics question, with the answer from NTA’s final answer key. Where our answers come from.