Physics · 2019
JEE Main · 10 April 2019, Shift 1 · Q22
The electric field of a plane electromagnetic wave is given by E = E_0 i cos ( k z) cos (ω t ) The corresponding magnetic field B is then given by:
The electric field of a plane electromagnetic wave is given by
$$\overrightarrow{\mathrm{E}}=\mathrm{E}_0 \hat{i} \cos (\mathrm{k} z) \cos (\omega \mathrm{t})
$$
The corresponding magnetic field $\displaystyle \vec{B}$ is then given by :
Official answer
(1)
$\displaystyle \vec{B}=\frac{E_0}{C} \hat{j} \sin (k z) \sin (\omega t)$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.