Physics · 2023
JEE Main · 13 April 2023, Shift 2 · Q32
The distance travelled by an object in time t is given by s =(2.5) t^2. The instantaneous speed of the object at t =5 s will be:
The distance travelled by an object in time t is given by $\displaystyle \mathrm{s}=(2.5) \mathrm{t}^2$. The instantaneous speed of the object at $\displaystyle \mathrm{t}=5 \mathrm{~s}$ will be:
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 25 \mathrm{~ms}^{-1}$
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.