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Physics · 2024

JEE Main · 6 April 2024, Shift 2 · Q57

A particle moves in a straight line so that its displacement x at any time t is given by x^2=1+t^2. Its acceleration at any time t is x^- n where n =…

A particle moves in a straight line so that its displacement $\displaystyle x$ at any time $\displaystyle t$ is given by $\displaystyle x^2=1+t^2$. Its acceleration at any time t is $\displaystyle x^{-\mathrm{n}}$ where $\displaystyle \mathrm{n}=$ $\displaystyle \_\_\_\_$.
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.