Physics · 2024
JEE Main · 29 January 2024, Shift 2 · Q32
A particle is moving in a straight line. The variation of position ' x ' as a function of time ' t ' is given as x=(t^3-6 t^2+20 t+15) m. The…
A particle is moving in a straight line. The variation of position ' $\displaystyle x$ ' as a function of time ' $\displaystyle t$ ' is given as $\displaystyle x=\left(t^3-6 t^2+20 t+15\right) m$. The velocity of the body when its acceleration becomes zero is :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 8 \mathrm{~m} / \mathrm{s}$
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.