Physics · 2022
JEE Main · 28 July 2022, Shift 1 · Q31
The dimensions of ((B^2)/(μ_0)) will be: (if μ_0: permeability of free space and B: magnetic field)
The dimensions of $\displaystyle \left(\frac{\mathrm{B}^2}{\mu_0}\right)$ will be :
(if $\displaystyle \mu_0$ : permeability of free space and B : magnetic field)
Official answer
(3)
$\displaystyle \left[\mathrm{M} \mathrm{L}^{-1} \mathrm{~T}^{-2}\right]$
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.