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Physics · 2022

JEE Main · 27 July 2022, Shift 2 · Q31

An expression of energy density is given by u=(α)/(β) sin ((α x)/(k t)), where α, β are constants, x is displacement, k is Boltzmann constant and t…

An expression of energy density is given by $\displaystyle u=\frac{\alpha}{\beta} \sin \left(\frac{\alpha x}{k \mathrm{t}}\right)$, where $\displaystyle \alpha, \beta$ are constants, $\displaystyle x$ is displacement, $\displaystyle k$ is Boltzmann constant and t is the temperature. The dimensions of $\displaystyle \beta$ will be :
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.