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Physics · 2025

JEE Main · 7 April 2025, Shift 2 · Q26

The dimension of √((μ_0)/(ε_0)) is equal to that of: ( μ_0= Vacuum permeability and ε_0= Vacuum permittivity)

The dimension of $\displaystyle \sqrt{\frac{\mu_0}{\epsilon_0}}$ is equal to that of : ( $\displaystyle \mu_0=$ Vacuum permeability and $\displaystyle \epsilon_0=$ Vacuum permittivity)
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JEE Main 2025 Physics question, with the answer from NTA’s final answer key. Where our answers come from.