Physics · 2026
JEE Main · 21 January 2026, Shift 1 · Q26
Consider a modified Bernoulli equation. (P+A/(B t^2))+ρ g(h+B t)+1/2 ρ V^2= constant If t has the dimension of time then the dimensions of A and B…
Consider a modified Bernoulli equation.
$$\left(P+\frac{A}{B t^2}\right)+\rho g(h+B t)+\frac{1}{2} \rho V^2=\text { constant }
$$
If $\displaystyle t$ has the dimension of time then the dimensions of $\displaystyle A$ and $\displaystyle B$ are $\displaystyle \_\_\_\_$, $\displaystyle \_\_\_\_$ respectively.
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle \left[\mathrm{ML}^0 \mathrm{~T}^{-1}\right] \text { and }\left[\mathrm{M}^0 \mathrm{LT}^{-1}\right]$
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.