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Physics · 2026

JEE Main · 21 January 2026, Shift 1 · Q26

Consider a modified Bernoulli equation. (P+A/(B t^2))+ρ g(h+B t)+1/2 ρ V^2= constant If t has the dimension of time then the dimensions of A and B…

Consider a modified Bernoulli equation. $$\left(P+\frac{A}{B t^2}\right)+\rho g(h+B t)+\frac{1}{2} \rho V^2=\text { constant } $$ If $\displaystyle t$ has the dimension of time then the dimensions of $\displaystyle A$ and $\displaystyle B$ are $\displaystyle \_\_\_\_$, $\displaystyle \_\_\_\_$ respectively.
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.