Physics · 2026
JEE Main · 2 April 2026, Shift 1 · Q26
The dimensional formula of 1/2 ε_o E^2 ( ε_o= permittivity of vacuum and E= electric field) is M^a L^b T^c. The value of 2 a-b+c= ____.
The dimensional formula of $\displaystyle \frac{1}{2} \epsilon_o E^2$ ( $\displaystyle \epsilon_o=$ permittivity of vacuum and $\displaystyle E=$ electric field) is $\displaystyle M^a L^b T^c$. The value of $\displaystyle 2 a-b+c=$ $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 1$
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.