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Physics · 2026

JEE Main · 23 January 2026, Shift 1 · Q43

The de Broglie wavelength of an oxygen molecule at 27^° C is x × 10^-12 m. The value of x is (take Planck's constant =6.63 × 10^-34 J.s, Boltzmann…

The de Broglie wavelength of an oxygen molecule at $\displaystyle 27^{\circ} \mathrm{C}$ is $\displaystyle x \times 10^{-12} \mathrm{~m}$. The value of $\displaystyle x$ is (take Planck's constant $\displaystyle =6.63 \times 10^{-34} \mathrm{~J}$.s, Boltzmann constant $\displaystyle =1.38 \times 10^{-23} \mathrm{~J} / \mathrm{K}$, mass of oxygen molecule $\displaystyle =5.31 \times 10^{-26} \mathrm{~kg}$ )
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.