Physics · 2026
JEE Main · 23 January 2026, Shift 1 · Q43
The de Broglie wavelength of an oxygen molecule at 27^° C is x × 10^-12 m. The value of x is (take Planck's constant =6.63 × 10^-34 J.s, Boltzmann…
The de Broglie wavelength of an oxygen molecule at $\displaystyle 27^{\circ} \mathrm{C}$ is $\displaystyle x \times 10^{-12} \mathrm{~m}$. The value of $\displaystyle x$ is (take Planck's constant $\displaystyle =6.63 \times 10^{-34} \mathrm{~J}$.s, Boltzmann constant $\displaystyle =1.38 \times 10^{-23} \mathrm{~J} / \mathrm{K}$, mass of oxygen molecule $\displaystyle =5.31 \times 10^{-26} \mathrm{~kg}$ )
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 26$
More from Dual Nature of Matter and Radiation
- Light source having wavelength 331 nm is used to generate photo-electrons whose stopping potential is 0.2 V. The work function of the used metal in…2026
- An electron is travelling with a velocity v in free space and when it enters a medium, its velocity is reduced by 20 %. The de Broglie wavelength of…2026
- The graph shows variation of stopping potential V_o with the frequency v of the incident radiation for three photosensitive metals X_1, X_2 and X_3.…2026
- An electron of mass m is moving in an electric field E=-2 E_o i(E_o=. constant.>0), with an initial velocity V=v_o i (v_o=. constant.>0). If λ_o=h/(4…2026
- K_1 and K_2 be the maximum kinetic energies of photoelectrons emitted from a surface of a given material for the light of wavelength λ_1 and λ_2,…2026
- A monochromatic source of light operating at 15 kW emits 2.5 × 10^22 photons / s. The region of an electromagnetic spectrum to which the emitted…2026
- For a certain metal, when monochromatic light of wavelength λ is incident, the stopping potential for photoelectrons is 3 V_o. When the same metal is…2026
- The de Broglie wavelength associated with an electron accelerated through a potential difference V is λ_e and the de Broglie wavelength associated…2026
JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.