Physics · 2026
JEE Main · 4 April 2026, Shift 2 · Q44
The de Broglie wavelength associated with an electron accelerated through a potential difference V is λ_e and the de Broglie wavelength associated…
The de Broglie wavelength associated with an electron accelerated through a potential difference V is $\displaystyle \lambda_{\mathrm{e}}$ and the de Broglie wavelength associated with a proton accelerated through the same potential difference is $\displaystyle \lambda_{\mathrm{p}}$. If their corresponding masses are $\displaystyle m_{\mathrm{e}}$ and $\displaystyle m_{\mathrm{p}}$, respectively, then the ratio of their de Broglie wavelengths $\displaystyle \left(\frac{\lambda_e}{\lambda_p}\right)$ is $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle \sqrt{\frac{m_p}{m_e}}$
More from Dual Nature of Matter and Radiation
- Light source having wavelength 331 nm is used to generate photo-electrons whose stopping potential is 0.2 V.…2026
- An electron is travelling with a velocity v in free space and when it enters a medium, its velocity is…2026
- The graph shows variation of stopping potential V_o with the frequency v of the incident radiation for three…2026
- An electron of mass m is moving in an electric field E=-2 E_o i(E_o=. constant.>0), with an initial velocity…2026
- K_1 and K_2 be the maximum kinetic energies of photoelectrons emitted from a surface of a given material for…2026
- A monochromatic source of light operating at 15 kW emits 2.5 × 10^22 photons / s. The region of an…2026
- For a certain metal, when monochromatic light of wavelength λ is incident, the stopping potential for…2026
- The de Broglie wavelength for an electron accelerated through the potential difference of V_1 volt is λ_1.…2026
JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.