SolveItJEE Main
Physics · 2026

JEE Main · 4 April 2026, Shift 2 · Q44

The de Broglie wavelength associated with an electron accelerated through a potential difference V is λ_e and the de Broglie wavelength associated…

The de Broglie wavelength associated with an electron accelerated through a potential difference V is $\displaystyle \lambda_{\mathrm{e}}$ and the de Broglie wavelength associated with a proton accelerated through the same potential difference is $\displaystyle \lambda_{\mathrm{p}}$. If their corresponding masses are $\displaystyle m_{\mathrm{e}}$ and $\displaystyle m_{\mathrm{p}}$, respectively, then the ratio of their de Broglie wavelengths $\displaystyle \left(\frac{\lambda_e}{\lambda_p}\right)$ is $\displaystyle \_\_\_\_$.
ShareWhatsAppTelegram

More from Dual Nature of Matter and Radiation

JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.